Find $h ( 7 )$ . $\eta ( x ) = \frac { 1 } { x + 8 }$
A) $\frac { 1 } { 15 }$
B) $\frac { 1 } { 16 }$
C) $\frac { 1 } { 13 }$
D) 16
E) 15

Name: Find $h ( 7 )$ . $\eta ( x ) = \frac { 1 } { x + 8 }$ A) $\frac { 1 } { 15 }$ B) $\frac { 1 } { 16 }$ C) $\frac { 1 } { 13 }$ D) 16 E) 15
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The Answer of Find $h ( 7 )$ . $\eta ( x ) = \frac { 1 } { x + 8 }$
A) $\frac { 1 } { 15 }$
B) $\frac { 1 } { 16 }$
C) $\frac { 1 } { 13 }$
D) 16
E) 15

Find h(7)h ( 7 )h(7) η(x)=1x+8\eta ( x ) = \frac { 1 } { x + 8 }η(x)=x+81​

Find $h ( 7 )$ $\eta ( x ) = \frac { 1 } { x + 8 }$