Factor the trinomial.

Question

Quizplus · Accepted Answer

There is no simple way to factor the given trinomial. Therefore, we need to use the quadratic formula which gives two distinct roots: $x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}$. Applying this formula with $a=1$, $b=11e$, and $c=11ebfe7e\_343b\_96cc\_ebedc693da70\_TBX8806\_11$, we get $x = -11e \pm \sqrt{(11e)^2-4(11ebfe7e\_343b\_96cc\_ebedc693da70\_TBX8806\_11)}{2}$. Simplifying the radicand gives $\sqrt{121e^2-4(11ebfe7e\_343b\_96cc\_ebedc693da70\_TBX8806\_11)} = \sqrt{e^2(121-44ebfe7e\_343b\_96cc\_ebedc693da70\_TBX8806\_11)} = \sqrt{e^2} \cdot \sqrt{121-44ebfe7e\_343b\_96cc\_ebedc693da70\_TBX8806\_11} = e \sqrt{121-44ebfe7e\_343b\_96cc\_ebedc693da70\_TBX8806\_11}$. Therefore, the two roots are $x=-11e+\frac{e\sqrt{121-44ebfe7e\_343b\_96cc\_ebedc693da70\_TBX8806\_11}}{2}$ and $x=-11e-\frac{e\sqrt{121-44ebfe7e\_343b\_96cc\_ebedc693da70\_TBX8806\_11}}{2}$. Neither of these expressions can be simplified further, so the only possible answer is (B), which is equivalent to the given trinomial.

Factor the Trinomial