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Public Class Exceptions

Question 70

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public class exceptions
{
    public static void main(String Args[])
    {
       int[] array = new int[3];
       try
       {
          for(int a=0;a<4;++a)
          {
             array[a] = a;
          }
          System.out.println(array);
       }
       catch(ArrayIndexOutOfBoundsException e)
       {
          System.out.println("Out of bounds");
       }
    }
}
In the above code, the line System.out.println(array); gets skipped when an exception occurs. Write a finally block that will execute, and will execute a System.out.println(array); if there is an exception.

Correct Answer:

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finally
{...

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