public static void main(String args[])
{
int a, b;
try
{
a = 0;
b = 42 / a;
System.out.println("This will not be printed.");
}

catch (ArithmeticException e)
{
System.out.println("Division by zero.");
}
System.out.println("After catch statement.");
}
The program above includes a try block and a catch clause that processes the ArithmeticException generated by the division-by-zero error. Explain how the try and catch blocks operate, and what the output will be following program execution.

Question

public static void main(String args[]) 
{ 
   int a, b; 
   try 
   { 
      a = 0; 
      b = 42 / a; 
      System.out.println("This will not be printed."); 
   }   
​ 
   catch (ArithmeticException e) 
   { 
      System.out.println("Division by zero."); 
   } 
   System.out.println("After catch statement."); 
}
The program above includes a try block and a catch clause that processes the ArithmeticException generated by the division-by-zero error. Explain how the try and catch blocks operate, and what the output will be following program execution.

Quizplus · Accepted Answer

The Answer of public static void main(String args[]) 
{ 
   int a, b; 
   try 
   { 
      a = 0; 
      b = 42 / a; 
      System.out.println("This will not be printed."); 
   }   
​ 
   catch (ArithmeticException e) 
   { 
      System.out.println("Division by zero."); 
   } 
   System.out.println("After catch statement."); 
}
The program above includes a try block and a catch clause that processes the ArithmeticException generated by the division-by-zero error. Explain how the try and catch blocks operate, and what the output will be following program execution.

Public Static Void Main(String Args[])