public abstract class Car
{
private String model;
public abstract void color();
public String getModel()
{
return model;
}
public void setModel(String modelName)
{
model = modelName;
}
}
public class Honda extends Car
{
public void color()
{
System.out.println("red");
}
}
public class Ford extends Car
{
public void color()
{
System.out.println("blue");
}
}
public class MyCars
{
public static void main(String[] args)
{
Honda myHonda = new Honda();
Ford myFord = new Ford();
myHonda.setModel("My Honda is ");
myFord.setModel("My Ford is ");
System.out.print(myHonda.getModel());
myHonda.color();
System.out.print(myFord.getModel());
myFord.color();
}
}
In the above code, the myHonda.getModel() and myHonda.color() method calls produce different output from when the same methods are used with myFord . Explain why this is the case.
Correct Answer:
Verified
View Answer
Unlock this answer now
Get Access to more Verified Answers free of charge
Q68: Q69: Give an example of how you can Q70: When you create classes for others to Q71: Q72: public interface FindTheError Q73: When you create a useful, extendable superclass, Unlock this Answer For Free Now! View this answer and more for free by performing one of the following actions Scan the QR code to install the App and get 2 free unlocks Unlock quizzes for free by uploading documents
{
void firstMethod(int anIntNum)