Solve the problem.
-The sum of the squares of the digits of a positive two-digit number is 13, and the units digit is 1 more than the tens digit. Find the number.
A) 23
B) 43
C) 32
D) 34

Question

Quizplus · Accepted Answer

The units digit is 1 more than the tens digit, so the number is 10x + (x + 1) = 11x + 1. The sum of the squares of the digits is 13, so x^2 + (x + 1)^2 = 13. Solving for x gives x = 2, so the number is 11(2) + 1 = 23.

Solve the Problem. -The Sum of the Squares of the Digits of a Digits