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-Fred throws a ball upward from a platform that is 10 feet above ground level. The height of the ball above the ground, in feet, is determined byy h $h = - 16 x ^ { 2 } + 72 x + 10,$ , where x is twhere x is he number of seconds after the ball is thrown.
Determine the height of the ball 4 seconds after the ball is thrown.
A)40 ft
B)52 ft
C)0 ft
D)42 ft

Question

Quizplus · Accepted Answer

To find the height of the ball 4 seconds after it is thrown, substitute $x = 4$ into the equation $h = -16x^2 + 72x + 10$. This gives $h = -16(4)^2 + 72(4) + 10 = -16(16) + 288 + 10 = -256 + 298 = 42$. Therefore, the height of the ball 4 seconds after it is thrown is 42 feet.

Use a Calculator to Solve h=−16x2+72x+10,h = - 16 x ^ { 2 } + 72 x + 10,h=−16x2+72x+10,

Use a Calculator to Solve $h = - 16 x ^ { 2 } + 72 x + 10,$