Find the sum of the infinite geometric series.
-$96 + 24 + 6 + \frac { 3 } { 2 } + \ldots$
A)128
B)126
C)96
D)- 32

Name: Find the sum of the infinite geometric series. -$96 + 24 + 6 + \frac { 3 } { 2 } + \ldots$ A)128 B)126 C)96 D)- 32
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Question

Quizplus · Accepted Answer

The sum of an infinite geometric series is given by $S = \frac{a}{1 - r}$, where $a$ is the first term and $r$ is the common ratio. Here, $a = 96$ and $r = \frac{24}{96} = \frac{1}{4}$. Thus, $S = \frac{96}{1 - \frac{1}{4}} = \frac{96}{\frac{3}{4}} = 128$.

Find the Sum of the Infinite Geometric Series 96+24+6+32+…96 + 24 + 6 + \frac { 3 } { 2 } + \ldots96+24+6+23​+…

Find the Sum of the Infinite Geometric Series $96 + 24 + 6 + \frac { 3 } { 2 } + \ldots$