Solve the problem.
-A formula used to determine the velocity v in feet per second per second of an object (neglecting air resistance) after it has fallen a certain height iss v $\mathrm { v } = \sqrt { 2 \mathrm { gh } },$ , where g is the acceler where g is the acceleation due to gravity and h is the height the
Object has fallen. If the acceleration g due to gravity on Earth is approximately 32 feet per second per second,
Find the velocity of a bowling ball after it has fallen 30 feet. (Round to the nearest tenth.)
A)31.0 ft/sec
B)43.8 ft/sec
C)1920 ft/sec
D)7.7 ft/sec

Question

Quizplus · Accepted Answer

Using the formula $ v = \sqrt{2gh} $, where $ g = 32 $ and $ h = 30 $, we calculate $ v = \sqrt{2 \times 32 \times 30} = \sqrt{1920} \approx 43.8 $ ft/sec.

Solve the Problem v=2gh,\mathrm { v } = \sqrt { 2 \mathrm { gh } },v=2gh​,

Solve the Problem $\mathrm { v } = \sqrt { 2 \mathrm { gh } },$