Solve the problem.
-Four bacteria are placed in a petri dish. The population will triple every day. The formula for the number of bacteria in the dish on day t is $\mathrm { N } ( \mathrm { t } ) = 4 ( 2 ) ^ { \mathrm { t } }$ where t is the number of days after the four bacteria are placed in the dish. How many bacteria are in the dish
Eight days after the four bacteria are placed in the dish?
A)144
B)12
C)256
D)48

Question

Quizplus · Accepted Answer

The formula given is incorrect based on the description; it should be $N(t) = 4 \times 3^t$ for tripling every day. Using the correct approach with $t = 8$, we calculate $N(8) = 4 \times 3^8 = 4 \times 6561 = 26244$. However, since this option is not available and assuming a typo in the formula description, using the provided formula $N(t) = 4(2)^t$ with $t = 8$, we get $N(8) = 4 \times 2^8 = 4 \times 256 = 1024$, which also doesn't match any options. Given the options and assuming a mistake in the problem statement or my interpretation, recalculating directly with the provided formula and options: $4(2)^8 = 4 \times 256 = 1024$, which again, does not match any provided options, indicating a misunderstanding in the question's premise or a mistake in my calculations based on the provided formula and the actual growth description. Without a correct match, and assuming a possible misinterpretation of the formula or question, the closest logical answer based on the initial problem description (tripling daily) is not directly represented in the options given.

Solve the Problem N(t)=4(2)t\mathrm { N } ( \mathrm { t } ) = 4 ( 2 ) ^ { \mathrm { t } }N(t)=4(2)t

Solve the Problem $\mathrm { N } ( \mathrm { t } ) = 4 ( 2 ) ^ { \mathrm { t } }$