Determine whether the given function is one-to-one. If it is one-to-one, find its inverse function.
-$f ( x ) = \sqrt { x - 1 } , x \geq 1$
A) $\mathrm { f } ^ { - 1 } ( \mathrm { x } ) = \mathrm { x } ^ { 2 } - 1 , \mathrm { x } \geq 0$
B) $f ^ { - 1 } ( x ) = ( x - 1 ) ^ { 2 } , x \geq 1$
C) $f^{-1}(x)=x^{2}+1, x \geq 0$
D)not a one-to-one function

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The Answer of Determine whether the given function is one-to-one. If it is one-to-one, find its inverse function.
-$f ( x ) = \sqrt { x - 1 } , x \geq 1$
A) $\mathrm { f } ^ { - 1 } ( \mathrm { x } ) = \mathrm { x } ^ { 2 } - 1 , \mathrm { x } \geq 0$
B) $f ^ { - 1 } ( x ) = ( x - 1 ) ^ { 2 } , x \geq 1$
C) $f^{-1}(x)=x^{2}+1, x \geq 0$
D)not a one-to-one function

Determine Whether the Given Function Is One-To-One f(x)=x−1,x≥1f ( x ) = \sqrt { x - 1 } , x \geq 1f(x)=x−1​,x≥1

Determine Whether the Given Function Is One-To-One $f ( x ) = \sqrt { x - 1 } , x \geq 1$