Determine whether the given function is one-to-one. If it is one-to-one, find its inverse function.
-$f ( x ) = x ^ { 2 } - 1 , x \geq 0$
A) $f ^ { - 1 } ( x ) = \sqrt { x } + 1 , x \geq 0$
B) $\mathrm { f } ^ { - 1 } ( \mathrm { x } ) = \sqrt { \mathrm { x } + 1 } , \mathrm { x } \geq - 1$
C) $f ^ { - 1 } ( x ) = \sqrt { x - 1 } , x \geq 1$
D)not a one-to-one function

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The Answer of Determine whether the given function is one-to-one. If it is one-to-one, find its inverse function.
-$f ( x ) = x ^ { 2 } - 1 , x \geq 0$
A) $f ^ { - 1 } ( x ) = \sqrt { x } + 1 , x \geq 0$
B) $\mathrm { f } ^ { - 1 } ( \mathrm { x } ) = \sqrt { \mathrm { x } + 1 } , \mathrm { x } \geq - 1$
C) $f ^ { - 1 } ( x ) = \sqrt { x - 1 } , x \geq 1$
D)not a one-to-one function

Determine Whether the Given Function Is One-To-One f(x)=x2−1,x≥0f ( x ) = x ^ { 2 } - 1 , x \geq 0f(x)=x2−1,x≥0

Determine Whether the Given Function Is One-To-One $f ( x ) = x ^ { 2 } - 1 , x \geq 0$