Determine whether the function is a one-to-one function.
-$$y = x ^ { 2 } + 7 , x \geq 0$$
A)Yes
B)No

Question

Quizplus · Accepted Answer

The function $y = x^2 + 7$ for $x \geq 0$ is a one-to-one function because, in the given domain $x \geq 0$, each x-value corresponds to exactly one y-value, and each y-value corresponds to exactly one x-value. The restriction $x \geq 0$ eliminates the possibility of having two different x-values (one positive and one negative) that would produce the same y-value, which would happen in the case of a standard quadratic function without domain restrictions.

Determine Whether the Function Is a One-To-One Function y=x2+7,x≥0y = x ^ { 2 } + 7 , x \geq 0y=x2+7,x≥0

Determine Whether the Function Is a One-To-One Function $y = x ^ { 2 } + 7 , x \geq 0$