In an area of the Midwest, records were kept on the relationship between the rainfall (in inches)and the yield of wheat (bushels per acre). Find the standard error of estimate, $\mathrm { Se } ,$ , given that ? = 4.379x + 4.267. $$\begin{array} { l | l | l | l | l | l | l | l | l | l | }
\text { Rain fall (in inches), } \mathrm { x } & 10.5 & 8.8 & 13.4 & 12.5 & 18.8 & 10.3 & 7.0 & 15.6 & 16.0 \
\hline \text { Yield (bushels per acre), y } & 50.5 & 46.2 & 58.8 & 59.0 & 82.4 & 49.2 & 31.9 & 76.0 & 78.8
\end{array}$$
A)3.529
B)4.759
C)2.813
D)1.332

Question

In an area of the Midwest, records were kept on the relationship between the rainfall (in inches)and the yield of wheat (bushels per acre). Find the standard error of estimate, $\mathrm { Se } ,$ , given that ? = 4.379x + 4.267. $$\begin{array} { l | l | l | l | l | l | l | l | l | l | } 
\text { Rain fall (in inches), } \mathrm { x } & 10.5 & 8.8 & 13.4 & 12.5 & 18.8 & 10.3 & 7.0 & 15.6 & 16.0 \
\hline \text { Yield (bushels per acre), y } & 50.5 & 46.2 & 58.8 & 59.0 & 82.4 & 49.2 & 31.9 & 76.0 & 78.8
\end{array}$$
A)3.529
B)4.759
C)2.813
D)1.332

Quizplus · Accepted Answer

The standard error of estimate is calculated using the formula $ Se = \sqrt{\frac{\sum (y - \hat{y})^2}{n-2}} $, where $ \hat{y} $ is the predicted value from the regression equation. After calculating the predicted values and the residuals, the sum of squared residuals is found, and the standard error is computed to be approximately 3.529.

In an Area of the Midwest, Records Were Kept on the Relationship