Solve.
-An object is thrown upward from the top of a 160-foot building with an initial velocity of 48 feet per second. The height h of the object after t seconds is given by the quadratic equation h = -16t2 + 48t + 160. When will the
Object hit the ground?
A)160 sec
B)-2 sec
C)2 sec
D)5 sec

Question

Quizplus · Accepted Answer

To find when the object hits the ground, we set the height $h = 0$ and solve the quadratic equation $-16t^2 + 48t + 160 = 0$. Factoring or using the quadratic formula, we find that $t = 5$ seconds is the positive solution that makes physical sense (time cannot be negative).

Solve. -An Object Is Thrown Upward from the Top of a a 160-Foot