Factor the trinomial completely.
- $4 x ^ { 3 } y + 36 x ^ { 2 } y ^ { 2 } + 81 x y ^ { 3 }$
A) $\left( 4 x ^ { 2 } y + x y \right) \left( x + 81 y ^ { 2 } \right)$
B) $x y ( 2 x - 9 y ) ^ { 2 }$
C) $x y ( 2 x + 9 y ) ^ { 2 }$
D) $x y ( 2 x + 9 y ) ( 2 x - 9 y )$

Question

Quizplus · Accepted Answer

Each term in the trinomial shares a common factor of $xy$, and the remaining trinomial is a perfect square. Factoring out $xy$ gives $xy(4x^2 + 36xy + 81y^2)$, which simplifies to $xy(2x + 9y)^2$.

Factor the Trinomial Completely 4x3y+36x2y2+81xy34 x ^ { 3 } y + 36 x ^ { 2 } y ^ { 2 } + 81 x y ^ { 3 }4x3y+36x2y2+81xy3

Factor the Trinomial Completely $4 x ^ { 3 } y + 36 x ^ { 2 } y ^ { 2 } + 81 x y ^ { 3 }$