Factor the trinomial completely.
-$x ^ { 3 } + 16 x ^ { 2 } + 64 x$
A)x(x + 8)(x - 8)
B) $\mathrm { x } ( \mathrm { x } + 8 ) ^ { 2 }$
C) $x ( x - 8 ) ^ { 2 }$
D)prime

Question

Quizplus · Accepted Answer

First, factor out the greatest common factor, which is $x$, to get $x(x^2 + 16x + 64)$. Then, notice that $x^2 + 16x + 64$ is a perfect square trinomial, factoring to $(x + 8)^2$. Thus, the complete factorization is $x(x + 8)^2$.

Factor the Trinomial Completely x3+16x2+64xx ^ { 3 } + 16 x ^ { 2 } + 64 xx3+16x2+64x

Factor the Trinomial Completely $x ^ { 3 } + 16 x ^ { 2 } + 64 x$