Factor the trinomial completely. -$6 x ^ { 2 } y ^ { 2 } - 5 x y ^ { 2 } - 25 y ^ { 2 }$ A)(3x - 5y)(2x + 5y) B)y²(x - 5)(6x + 5) C) $y ^ { 2 } ( 2 x - 5 ) ( 3 x + 5 )$ D)(2x - 5y)(3x + 5y)

Question

Quizplus · Accepted Answer

First, factor out the greatest common factor, which is $y^2$, resulting in $y^2(6x^2 - 5x - 25)$. Then, factor the quadratic inside the parentheses to get $y^2(2x - 5)(3x + 5)$.

Factor the Trinomial Completely 6x2y2−5xy2−25y26 x ^ { 2 } y ^ { 2 } - 5 x y ^ { 2 } - 25 y ^ { 2 }6x2y2−5xy2−25y2

Factor the Trinomial Completely $6 x ^ { 2 } y ^ { 2 } - 5 x y ^ { 2 } - 25 y ^ { 2 }$