Factor the trinomial completely.
-9 $9 p ^ { 4 } - 42 p ^ { 3 } + 49 p ^ { 2 }$
A) $p ^ { 2 } ( 3 p - 7 ) ( 3 p + 7 )$
B) $p ^ { 2 } ( 3 p + 7 ) ^ { 2 }$
C) $p ^ { 2 } ( 3 p - 7 ) ^ { 2 }$
D) $p ^ { 2 } ( 9 p + 1 ) ( p + 49 )$

Question

Quizplus · Accepted Answer

First, factor out the greatest common factor, which is $p^2$, resulting in $p^2(9p^2 - 42p + 49)$. The trinomial inside the parentheses factors further into $(3p - 7)^2$, making the complete factorization $p^2(3p - 7)^2$.

Factor the Trinomial Completely 9p4−42p3+49p29 p ^ { 4 } - 42 p ^ { 3 } + 49 p ^ { 2 }9p4−42p3+49p2

Factor the Trinomial Completely $9 p ^ { 4 } - 42 p ^ { 3 } + 49 p ^ { 2 }$