Factor the trinomial completely.
-$6 a ^ { 2 } - 7 a b - 3 b ^ { 2 }$
A)(6a + b)(a - 3b)
B)(3a + b)(2a - 3b)
C)(3a - b)(2a + 3b)
D)prime

Question

Quizplus · Accepted Answer

The correct factorization of $6a^2 - 7ab - 3b^2$ is found by looking for two numbers that multiply to $6 \times -3 = -18$ and add to $-7$. These numbers are $-9$ and $2$. Thus, the trinomial can be rewritten and factored as $3a(2a - 3b) + b(2a - 3b) = (3a + b)(2a - 3b)$.

Factor the Trinomial Completely 6a2−7ab−3b26 a ^ { 2 } - 7 a b - 3 b ^ { 2 }6a2−7ab−3b2

Factor the Trinomial Completely $6 a ^ { 2 } - 7 a b - 3 b ^ { 2 }$