Perform the indicated operation and simplify if possible.
-$\frac { y ^ { 2 } - 6 y + 8 } { 4 y + 8 } \cdot \frac { y + 2 } { 3 y - 12 }$
A) $\frac { \mathrm { y } - 4 } { 12 }$
B) $\frac { ( y - 2 ) ( y - 4 ) } { 12 ( y + 4 ) }$
C) $\frac { y - 2 } { 12 }$
D) $\frac { y + 2 } { 12 }$

Question

Quizplus · Accepted Answer

First, factorize both the numerator and the denominator where possible. The first fraction becomes $\frac{(y-2)(y-4)}{4(y+2)}$, and the second fraction simplifies to $\frac{y+2}{3(y-4)}$. When you multiply these fractions, the terms $y+2$ and $y-4$ cancel out, leaving $\frac{y-2}{12}$.

Perform the Indicated Operation and Simplify If Possible y2−6y+84y+8⋅y+23y−12\frac { y ^ { 2 } - 6 y + 8 } { 4 y + 8 } \cdot \frac { y + 2 } { 3 y - 12 }4y+8y2−6y+8​⋅3y−12y+2​

Perform the Indicated Operation and Simplify If Possible $\frac { y ^ { 2 } - 6 y + 8 } { 4 y + 8 } \cdot \frac { y + 2 } { 3 y - 12 }$