Solve the equation for the indicated variable.
-A = $\frac { h ( a + b ) } { 2 }$ for a
A)a = $\frac { \mathrm { A } - \mathrm { hb } } { 2 \mathrm {~h} }$
B)a = $\frac { 2 \mathrm { Ab } - \mathrm { h } } { \mathrm { h } }$
C)a = $\frac { \mathrm { hb } - 2 \mathrm {~A} } { \mathrm {~h} }$
D)a = $\frac { 2 \mathrm {~A} - \mathrm { hb } } { \mathrm { h } }$

Question

Quizplus · Accepted Answer

To solve for $a$, start with $A = \frac{h(a+b)}{2}$. Multiply both sides by 2 to get rid of the denominator: $2A = h(a+b)$. Then, isolate $a$ by subtracting $hb$ from both sides: $2A - hb = ha$. Finally, divide both sides by $h$ to solve for $a$, resulting in $a = \frac{2A - hb}{h}$.

Solve the Equation for the Indicated Variable h(a+b)2\frac { h ( a + b ) } { 2 }2h(a+b)​

Solve the Equation for the Indicated Variable $\frac { h ( a + b ) } { 2 }$