Solve the problem.
-Two angles are complementary if the sum of their measures is 90°. If the measure of one angle is given by $\left( \frac { 1080 } { y } \right) ^ { \circ }$ and the and the measure of its complement is given by ( $\left( \frac { 540 } { y } \right) ^ {\circ }$ °, find the measures of the two angles.
A)60°, 30°
B)9°, 81°
C)120°, 60°
D)18°, 72°

Question

Solve the problem.
-Two angles are complementary if the sum of their measures is 90°. If the measure of one angle is given by $\left( \frac { 1080 } { y } \right) ^ { \circ }$ and the and the measure of its complement is given by ( $\left( \frac { 540 } { y } \right) ^ {\circ  }$ °, find the measures of the two angles.
A)60°, 30°
B)9°, 81°
C)120°, 60°
D)18°, 72°

Quizplus · Accepted Answer

The sum of the measures of the two angles is 90°, so we have:$\left( \frac { 1080 } { y } \right) ^ { \circ } + \left( \frac { 540 } { y } \right) ^ {\circ  } = 90 ^ { \circ }$Solving for y, we get:$\frac { 1080 } { y } + \frac { 540 } { y } = 90$$\frac { 1620 } { y } = 90$$y = 18$So the measure of one angle is:$\left( \frac { 1080 } { 18 } \right) ^ { \circ } = 60 ^ { \circ }$And the measure of its complement is:$\left( \frac { 540 } { 18 } \right) ^ {\circ  } = 30 ^ { \circ }$

Solve the Problem (1080y)∘\left( \frac { 1080 } { y } \right) ^ { \circ }(y1080​)∘

Solve the Problem $\left( \frac { 1080 } { y } \right) ^ { \circ }$