Solve the problem.
-A formula used to determine the velocity v in feet per second of an object (neglecting air resistance)after it has fallen a certain height isllen a certain height is $\mathrm { v } = \sqrt { 2 \mathrm { gh } }$ , where g is the acceleration due to gravity and h is the height the object has Fallen. If the acceleration g due to gravity on Earth is approximately 32 feet per second, find the velocity of a Bowling ball after it has fallen 90 feet. (Round to the nearest tenth.)
A)5760 ft per sec
B)53.7 ft per sec
C)13.4 ft per sec
D)75.9 ft per sec

Question

Quizplus · Accepted Answer

The formula for velocity is v = sqrt(2gh). Substituting g = 32 ft/s^2 and h = 90 ft, we get v = sqrt(2 * 32 * 90) = sqrt(5760) = 75.9 ft/s (rounded to the nearest tenth).

Solve the Problem v=2gh\mathrm { v } = \sqrt { 2 \mathrm { gh } }v=2gh​

Solve the Problem $\mathrm { v } = \sqrt { 2 \mathrm { gh } }$