Solve the problem.
-The height of a triangle is 4 times the length of the base. The area of the triangle is 162 square meters. Find the height and base of the triangle.
A)base:: $\frac { 9 \sqrt { 2 } } { 2 }$ m, m, height: 18 $18 \sqrt { 2 } \mathrm {~m}$
B)base: 9 m, height: 36 m
C)base: 36 m, height: 72 m
D)base:: $\frac { 9 } { 2 }$ m, m, height: 72 m

Question

Solve the problem.
-The height of a triangle is 4 times the length of the base. The area of the triangle is 162 square meters. Find the height and base of the triangle. 
A)base:: $\frac { 9 \sqrt { 2 } } { 2 }$ m, m, height: 18 $18 \sqrt { 2 } \mathrm {~m}$ 
B)base: 9 m, height: 36 m 
C)base: 36 m, height: 72 m 
D)base:: $\frac { 9 } { 2 }$ m, m, height: 72 m

Quizplus · Accepted Answer

The Answer of Solve the problem.
-The height of a triangle is 4 times the length of the base. The area of the triangle is 162 square meters. Find the height and base of the triangle. 
A)base:: $\frac { 9 \sqrt { 2 } } { 2 }$ m, m, height: 18 $18 \sqrt { 2 } \mathrm {~m}$ 
B)base: 9 m, height: 36 m 
C)base: 36 m, height: 72 m 
D)base:: $\frac { 9 } { 2 }$ m, m, height: 72 m

Solve the Problem 922\frac { 9 \sqrt { 2 } } { 2 }292​​

Solve the Problem $\frac { 9 \sqrt { 2 } } { 2 }$