Use the quadratic formula to solve the quadratic equation.
-$4 n ^ { 2 } = - 10 n - 1$
A) $n = \frac { - 10 \pm \sqrt { 21 } } { 4 }$
B) $n = \frac { - 5 \pm \sqrt { 21 } } { 4 }$
C) $\mathrm { n } = \frac { - 5 \pm \sqrt { 21 } } { 8 }$
D) $n = \frac { - 5 \pm \sqrt { 29 } } { 4 }$

Question

Quizplus · Accepted Answer

First, rearrange the equation to standard form: $4n^2 + 10n + 1 = 0$. Then, apply the quadratic formula $n = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$ with $a = 4$, $b = 10$, and $c = 1$, resulting in $n = \frac{-10 \pm \sqrt{100 - 16}}{8} = \frac{-10 \pm \sqrt{84}}{8} = \frac{-5 \pm \sqrt{21}}{4}$.

Use the Quadratic Formula to Solve the Quadratic Equation 4n2=−10n−14 n ^ { 2 } = - 10 n - 14n2=−10n−1

Use the Quadratic Formula to Solve the Quadratic Equation $4 n ^ { 2 } = - 10 n - 1$