Use the square root property to solve the quadratic equation.
-$6 x ^ { 2 } + 8 x + 1 = 0$
A) $\frac { - 4 \pm \sqrt { 10 } } { 6 }$
B) $\frac { - 4 \pm \sqrt { 22 } } { 6 }$
C) $\frac { - 8 \pm \sqrt { 10 } } { 6 }$
D) $\frac { - 4 \pm \sqrt { 10 } } { 12 }$

Question

Quizplus · Accepted Answer

The quadratic equation $6x^2 + 8x + 1 = 0$ can be solved using the quadratic formula $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$, where $a = 6$, $b = 8$, and $c = 1$. Plugging these values into the formula gives $x = \frac{-8 \pm \sqrt{64 - 24}}{12} = \frac{-8 \pm \sqrt{40}}{12}$. Simplifying $\sqrt{40}$ to $2\sqrt{10}$ and dividing numerator and denominator by 2 gives $x = \frac{-4 \pm \sqrt{10}}{6}$, which matches choice A.

Use the Square Root Property to Solve the Quadratic Equation 6x2+8x+1=06 x ^ { 2 } + 8 x + 1 = 06x2+8x+1=0

Use the Square Root Property to Solve the Quadratic Equation $6 x ^ { 2 } + 8 x + 1 = 0$