Use the square root property to solve the quadratic equation.
-$3 y ^ { 2 } + 12 y + 7 = 0$
A) $- 2 \pm \frac { \sqrt { 15 } } { 3 }$
B) $- 2 \pm \frac { \sqrt { 15 } } { 6 }$
C) $2 \pm \frac { \sqrt { 15 } } { 6 }$
D) $2 \pm \frac { \sqrt { 15 } } { 3 }$

Question

Use the square root property to solve the quadratic equation.
-$3 y ^ { 2 } + 12 y + 7 = 0$
A)  $- 2 \pm \frac { \sqrt { 15 } } { 3 }$
B)  $- 2 \pm \frac { \sqrt { 15 } } { 6 }$
C) $2 \pm \frac { \sqrt { 15 } } { 6 }$
D) $2 \pm \frac { \sqrt { 15 } } { 3 }$

Quizplus · Accepted Answer

The quadratic equation can be solved using the quadratic formula: $y = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$. For $3y^2 + 12y + 7 = 0$, $a = 3$, $b = 12$, and $c = 7$. Plugging these into the formula gives the solutions $-2 \pm \frac{\sqrt{15}}{3}$.

Use the Square Root Property to Solve the Quadratic Equation 3y2+12y+7=03 y ^ { 2 } + 12 y + 7 = 03y2+12y+7=0

Use the Square Root Property to Solve the Quadratic Equation $3 y ^ { 2 } + 12 y + 7 = 0$