Solve the inequality. Write the solution set in interval notation.
-(x + 1)(x - 1)(x - 5) 0
A)(-1, 1) $\cup$ (5, ?)
B)(5, ?)
C)(-?, 1)
D)(-?, -1)) $\cup$ (1, 5)

Question

Solve the inequality. Write the solution set in interval notation.
-(x + 1)(x - 1)(x - 5)> 0
A)(-1, 1) $\cup$ (5, ?)
B)(5, ?)
C)(-?, 1)
D)(-?, -1)) $\cup$ (1, 5)

Quizplus · Accepted Answer

The inequality is true when (x + 1) > 0 and (x - 1) > 0 and (x - 5) > 0, or when (x + 1) < 0 and (x - 1) < 0 and (x - 5) < 0. The first case occurs when x > -1 and x > 1 and x > 5, which is never. The second case occurs when x < -1 and x < 1 and x < 5, which is when x is between -1 and 1 or x is less than -1 or x is greater than 5. So the solution set is (-1, 1) $\cup$ (5, $\infin$).

Solve the Inequality ∪\cup∪ (5, ?) B)(5, ?) C)(-?, 1) D)(-?, -1))

Solve the Inequality $\cup$ (5, ?)
B)(5, ?)
C)(-?, 1)
D)(-?, -1))