Solve.
-Claire has received scores of 85, 88, 87, and 85 on her algebra tests. What is the minimum score she must receive on the fifth test to have an overall test score average of at least 88? (Hint: The average of a list of numbers is their
Sum divided by the number of numbers in the list.)
A)95
B)93
C)94
D)96

Question

Quizplus · Accepted Answer

To find out the minimum score Claire needs to get an overall average of 88 or better, we can use the formula:

average = sum of all scores / number of scores

We know Claire has taken 4 tests so far and received scores of 85, 88, 87, and 85. Let's call her fifth and final score "x".

We can set up the equation:

(85 + 88 + 87 + 85 + x) / 5 ≥ 88

Simplifying the left side:

(340 + x) / 5 ≥ 88

Multiplying both sides by 5:

340 + x ≥ 440

Subtracting 340 from both sides:

x ≥ 100

So the minimum score Claire must receive on the fifth test to have an overall average of at least 88 is 100. However, since the highest possible score is 100, she cannot achieve this. Thus, the best option is the next highest score which is 95 (option A).

Solve. -Claire Has Received Scores of 85, 88, 87, and 85