Find (f/g)(x). $f ( x ) = 4 x ^ { 2 } - 8 x$ $g ( x ) = - 7 - x$
A) $( f / g ) ( x ) = \frac { 4 x ^ { 2 } - 8 x } { - 7 - x } , x \neq 7$
B) $( f / g ) ( x ) = \frac { 4 x ^ { 2 } - 8 x } { - 7 - x } , x \neq - 7$
C) $( f / g ) ( x ) = \frac { 4 x ^ { 2 } - 8 x } { - 7 - x } , x \neq 0$
D) $( f / g ) ( x ) = \frac { 4 x - 8 } { - 7 } , x \neq 0$
E) $( f / g ) ( x ) = - \frac { 4 x ^ { 2 } } { 7 } + 8 , x \neq 0$

Question

Quizplus · Accepted Answer

The division of $f(x)$ by $g(x)$ gives $\frac{4x^2 - 8x}{-7 - x}$. The condition $x \neq -7$ ensures the denominator is not zero, making the division valid.

Find (F/g)(x) f(x)=4x2−8xf ( x ) = 4 x ^ { 2 } - 8 xf(x)=4x2−8x

Find (F/g)(x) $f ( x ) = 4 x ^ { 2 } - 8 x$