Solve the system by the method of substitution. $\left\{ \begin{array} { l }
y = x ^ { 3 } + 2 x ^ { 2 } - 1 \
y = x ^ { 2 } + 12 x - 1
\end{array} \right.$
A)(-4, -33), (-3, -28), (1, 12)
B)(-4, -33), (-1, -12)
C)(3, 44), (1, 12)
D)(-4, -33), (3, 44), (0, -1)
E)no real solution

Question

Solve the system by the method of substitution. $\left\{ \begin{array} { l } 
y = x ^ { 3 } + 2 x ^ { 2 } - 1 \
y = x ^ { 2 } + 12 x - 1
\end{array} \right.$
A)(-4, -33), (-3, -28), (1, 12)
B)(-4, -33), (-1, -12)
C)(3, 44), (1, 12)
D)(-4, -33), (3, 44), (0, -1)
E)no real solution

Quizplus · Accepted Answer

The system has three solutions: (-4, -33), (3, 44), and (0, -1).

Solve the System by the Method of Substitution {y=x3+2x2−1y=x2+12x−1\left\{ \begin{array} { l } y = x ^ { 3 } + 2 x ^ { 2 } - 1 \\y = x ^ { 2 } + 12 x - 1\end{array} \right.{y=x3+2x2−1y=x2+12x−1​

Solve the System by the Method of Substitution $\left\{ \begin{array} { l } y = x ^ { 3 } + 2 x ^ { 2 } - 1 \\y = x ^ { 2 } + 12 x - 1\end{array} \right.$