Use the matrix capabilities of a graphing utility to solve the following system of linear equations: $\left\{ \begin{aligned}
- 16 x + 16 y + 24 z & = 2 \
8 x - 8 y & = - 1 \
8 y + 32 z & = 5
\end{aligned} \right.$
A) $\left[ \begin{array} { l }
x \
y \
z
\end{array} \right] = \left[ \begin{array} { c }
\frac { 1 } { 4 } \
0 \
- \frac { 3 } { 8 }
\end{array} \right]$
B) $\left[ \begin{array} { l }
x \
y \
z
\end{array} \right] = \left[ \begin{array} { c }
\frac { 3 } { 8 } \\
- \frac { 1 } { 4 } \\
\frac { 1 } { 4 }
\end{array} \right]$
C) $\left[ \begin{array} { c }
x \
y \
z
\end{array} \right] = \left[ \begin{array} { c }
- \frac { 3 } { 8 } \\
\frac { 1 } { 4 } \\
\frac { 1 } { 8 }
\end{array} \right]$
D) $\left[ \begin{array} { l }
x \
y \
z
\end{array} \right] = \left[ \begin{array} { c }
\frac { 1 } { 8 } \\
- \frac { 1 } { 2 } \\
\frac { 1 } { 4 }
\end{array} \right]$
E) $\left[ \begin{array} { c }
x \
y \
z
\end{array} \right] = \left[ \begin{array} { c }
\frac { 1 } { 2 } \\
\frac { 5 } { 8 } \\
0
\end{array} \right]$

Question

Use the matrix capabilities of a graphing utility to solve the following system of linear equations: $\left\{ \begin{aligned}
- 16 x + 16 y + 24 z & = 2 \
8 x - 8 y & = - 1 \
8 y + 32 z & = 5
\end{aligned} \right.$
A) $\left[ \begin{array} { l } 
x \
y \
z
\end{array} \right] = \left[ \begin{array} { c } 
\frac { 1 } { 4 } \
0 \
- \frac { 3 } { 8 }
\end{array} \right]$
B) $\left[ \begin{array} { l } 
x \
y \
z
\end{array} \right] = \left[ \begin{array} { c } 
\frac { 3 } { 8 } \\
- \frac { 1 } { 4 } \\
\frac { 1 } { 4 }
\end{array} \right]$
C) $\left[ \begin{array} { c } 
x \
y \
z
\end{array} \right] = \left[ \begin{array} { c } 
- \frac { 3 } { 8 } \\
\frac { 1 } { 4 } \\
\frac { 1 } { 8 }
\end{array} \right]$
D) $\left[ \begin{array} { l } 
x \
y \
z
\end{array} \right] = \left[ \begin{array} { c } 
\frac { 1 } { 8 } \\
- \frac { 1 } { 2 } \\
\frac { 1 } { 4 }
\end{array} \right]$
E) $\left[ \begin{array} { c } 
x \
y \
z
\end{array} \right] = \left[ \begin{array} { c } 
\frac { 1 } { 2 } \\
\frac { 5 } { 8 } \\
0
\end{array} \right]$

Quizplus · Accepted Answer

The Answer of Use the matrix capabilities of a graphing utility to solve the following system of linear equations: $\left\{ \begin{aligned}
- 16 x + 16 y + 24 z & = 2 \
8 x - 8 y & = - 1 \
8 y + 32 z & = 5
\end{aligned} \right.$
A) $\left[ \begin{array} { l } 
x \
y \
z
\end{array} \right] = \left[ \begin{array} { c } 
\frac { 1 } { 4 } \
0 \
- \frac { 3 } { 8 }
\end{array} \right]$
B) $\left[ \begin{array} { l } 
x \
y \
z
\end{array} \right] = \left[ \begin{array} { c } 
\frac { 3 } { 8 } \\
- \frac { 1 } { 4 } \\
\frac { 1 } { 4 }
\end{array} \right]$
C) $\left[ \begin{array} { c } 
x \
y \
z
\end{array} \right] = \left[ \begin{array} { c } 
- \frac { 3 } { 8 } \\
\frac { 1 } { 4 } \\
\frac { 1 } { 8 }
\end{array} \right]$
D) $\left[ \begin{array} { l } 
x \
y \
z
\end{array} \right] = \left[ \begin{array} { c } 
\frac { 1 } { 8 } \\
- \frac { 1 } { 2 } \\
\frac { 1 } { 4 }
\end{array} \right]$
E) $\left[ \begin{array} { c } 
x \
y \
z
\end{array} \right] = \left[ \begin{array} { c } 
\frac { 1 } { 2 } \\
\frac { 5 } { 8 } \\
0
\end{array} \right]$

Use the Matrix Capabilities of a Graphing Utility to Solve {−16x+16y+24z=28x−8y=−18y+32z=5\left\{ \begin{aligned}- 16 x + 16 y + 24 z & = 2 \\8 x - 8 y & = - 1 \\8 y + 32 z & = 5\end{aligned} \right.⎩⎨⎧​−16x+16y+24z8x−8y8y+32z​=2=−1=5​

Use the Matrix Capabilities of a Graphing Utility to Solve $\left\{ \begin{aligned}- 16 x + 16 y + 24 z & = 2 \\8 x - 8 y & = - 1 \\8 y + 32 z & = 5\end{aligned} \right.$