Find the indefinite integral. $\int e ^ { - 4 y } d y$
A) $- 4 e ^ { - 4 y } + C$
B) $- 4 e ^ { - 5 y } + C$
C) $- \frac { 1 } { 4 } e ^ { - 5 y } + C$
D) $- \frac { 1 } { 4 } e ^ { - 4 y } + C$
E) $- \frac { 1 } { 4 } e ^ { \frac { - 1 } { 4 } y } + C$

Question

Quizplus · Accepted Answer

The integral of $e^{-4y}$ with respect to $y$ is $-\frac{1}{4}e^{-4y} + C$, because when you differentiate $-\frac{1}{4}e^{-4y}$ with respect to $y$, you get $e^{-4y}$, taking into account the chain rule which introduces a factor of $-4$ from the derivative of the exponent $-4y$, which is then cancelled by the $-\frac{1}{4}$ in front.

Find the Indefinite Integral ∫e−4ydy\int e ^ { - 4 y } d y∫e−4ydy

Find the Indefinite Integral $\int e ^ { - 4 y } d y$