Find the coordinates of the point that is located six units behind of the yz-plane, six units to the left of the xz-plane, and seven units below of the xy-plane.
A) $( - 6 , - 6 , - 7 )$
B) $( 6 , - 6 , - 7 )$
C) $( 6,6 , - 7 )$
D) $( - 6,6 , - 7 )$
E) $( - 6,6,7 )$

Question

Quizplus · Accepted Answer

The coordinates of a point in 3D space are given as $(x, y, z)$, where $x$ is the distance from the yz-plane, $y$ is the distance from the xz-plane, and $z$ is the distance from the xy-plane. A negative value indicates the direction is opposite to the positive axis direction. Thus, six units behind the yz-plane means $x = -6$, six units to the left of the xz-plane means $y = -6$, and seven units below the xy-plane means $z = -7$. Therefore, the coordinates are $(-6, -6, -7)$.

Find the Coordinates of the Point That Is Located Six (−6,−6,−7)( - 6 , - 6 , - 7 )(−6,−6,−7)

Find the Coordinates of the Point That Is Located Six $( - 6 , - 6 , - 7 )$