Find the derivative of the trigonometric function. $y = \cos 3 x + \sin ^ { 2 } x$
A) $- 3 \sin 3 x + 2 \sin x \cos x$
B) $3 \sin 3 x - 2 \sin x \cos x$
C) $3 \sin 3 x + 2 \sin ^ { 2 } x \cos x$
D) $- \sin 3 x + 2 \sin ^ { 2 } x \cos ^ { 2 } x$
E) $- 3 \sin ^ { 2 } x + \sin ^ { 2 } x \cos ^ { 2 } x$

Question

Quizplus · Accepted Answer

The derivative of $y = \cos 3x + \sin^2 x$ is found by applying the chain rule and the derivative of the sine function. The derivative of $\cos 3x$ is $-3 \sin 3x$, and the derivative of $\sin^2 x$ is $2\sin x \cos x$, using the chain rule and the derivative of $\sin x$, which is $\cos x$.

Find the Derivative of the Trigonometric Function y=cos⁡3x+sin⁡2xy = \cos 3 x + \sin ^ { 2 } xy=cos3x+sin2x

Find the Derivative of the Trigonometric Function $y = \cos 3 x + \sin ^ { 2 } x$