If a ball is thrown directly upward with a velocity of 48 ft/s, its height (in feet) after t seconds is givenby $y = 48 t - 16 t ^ { 2 }$
. What is the maximum height attained by the ball?

Question

If a ball is thrown directly upward with a velocity of 48 ft/s, its height (in feet) after t seconds is givenby $y = 48 t - 16 t ^ { 2 }$ 
. What is the maximum height attained by the ball?

Quizplus · Accepted Answer

The Answer of If a ball is thrown directly upward with a velocity of 48 ft/s, its height (in feet) after t seconds is givenby $y = 48 t - 16 t ^ { 2 }$ 
. What is the maximum height attained by the ball?

If a Ball Is Thrown Directly Upward with a Velocity y=48t−16t2y = 48 t - 16 t ^ { 2 }y=48t−16t2

If a Ball Is Thrown Directly Upward with a Velocity $y = 48 t - 16 t ^ { 2 }$