Factor the expression completely. $x ^ { 4 } + 5 x ^ { 3 } - 6 x ^ { 2 }$
A) $x ^ { 2 } ( x - 1 ) ( x + 6 )$
B) $x ^ { 2 } ( x - 4 ) ( x - 5 )$
C) $x ^ { 2 } ( x - 4 ) ( x + 5 )$
D) $x ^ { 2 } ( x - 1 ) ( x + 5 )$
E) $x ^ { 2 } ( x - 4 ) ( x + 6 )$

Question

Quizplus · Accepted Answer

First, factor out the greatest common factor, which is $x^2$, resulting in $x^2(x^2 + 5x - 6)$. Then, factor the quadratic $x^2 + 5x - 6$ into $(x - 1)(x + 6)$.

Factor the Expression Completely x4+5x3−6x2x ^ { 4 } + 5 x ^ { 3 } - 6 x ^ { 2 }x4+5x3−6x2

Factor the Expression Completely $x ^ { 4 } + 5 x ^ { 3 } - 6 x ^ { 2 }$