Answer the question.
-Police use a formula $s = S \sqrt { \frac { l } { L } }$, where $S$ is the test-car speed and $L$ is the test-skid length, to find the actual speed $s$ in an accident which left a skid mark of l. Find the speed (nearest whole mph) when $S = 54 \mathrm { mph }$, $l = 150 \mathrm { ft } , \mathrm { L } = 100 \mathrm { ft }$.
A) $66 \mathrm { mph }$
B) $44 \mathrm { mph }$
C) $81 \mathrm { mph }$
D) $104 \mathrm { mph }$

Question

Quizplus · Accepted Answer

Using the formula $s = S \sqrt { \frac { l } { L } }$, substituting $S = 54 \mathrm { mph }$, $l = 150 \mathrm { ft }$, and $L = 100 \mathrm { ft }$, we get $s = 54 \sqrt { \frac { 150 } { 100 } } = 54 \sqrt { 1.5 } \approx 66 \mathrm { mph }$.

Answer the Question s=SlLs = S \sqrt { \frac { l } { L } }s=SLl​​

Answer the Question $s = S \sqrt { \frac { l } { L } }$