Solve the problem using the elimination method.
-There were 490 people at a play. The admission price was $\$ 3$ for adults and $\$ 1$ for children. The admission receipts were $\$ 1070$. How many adults and how many children attended?
A) 290 adults and 200 children
B) 267 adults and 223 children
C) 100 adults and 390 children
D) 200 adults and 290 children

Question

Quizplus · Accepted Answer

Let the number of adults be $x$ and the number of children be $y$. We have two equations: $x + y = 490$ and $3x + y = 1070$. Subtracting the first equation from the second gives $2x = 580$, so $x = 290$. Substituting $x = 290$ into the first equation gives $y = 200$.

Solve the Problem Using the Elimination Method $3\$ 3$3 For Adults And

Solve the Problem Using the Elimination Method $\$ 3$ For Adults And