The helix $\mathbf { r } _ { 1 } ( t ) = 2 \cos t \mathbf { i } + \sin t \mathbf { j } + t \mathbf { k }$ intersects the curve $\mathbf { r } _ { 2 } ( t ) = ( 2 + t ) \mathbf { i } + 10 t ^ { 2 } \mathbf { j } + 9 t ^ { 3 } \mathbf { k }$ at the point $( 2,0,0 )$. Find the angle of intersection.

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The Answer of The helix $\mathbf { r } _ { 1 } ( t ) = 2 \cos t \mathbf { i } + \sin t \mathbf { j } + t \mathbf { k }$ intersects the curve $\mathbf { r } _ { 2 } ( t ) = ( 2 + t ) \mathbf { i } + 10 t ^ { 2 } \mathbf { j } + 9 t ^ { 3 } \mathbf { k }$ at the point $( 2,0,0 )$. Find the angle of intersection.

The Helix r1(t)=2cos⁡ti+sin⁡tj+tk\mathbf { r } _ { 1 } ( t ) = 2 \cos t \mathbf { i } + \sin t \mathbf { j } + t \mathbf { k }r1​(t)=2costi+sintj+tk

The Helix $\mathbf { r } _ { 1 } ( t ) = 2 \cos t \mathbf { i } + \sin t \mathbf { j } + t \mathbf { k }$