Find the acceleration of a particle with the given position function.
$$\mathbf { r } ( t ) = 9 \sin t \mathbf { i } + 10 t \mathbf { j } - 8 \cos t \mathbf { k }$$

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The Answer of Find the acceleration of a particle with the given position function.
$$\mathbf { r } ( t ) = 9 \sin t \mathbf { i } + 10 t \mathbf { j } - 8 \cos t \mathbf { k }$$

Find the Acceleration of a Particle with the Given Position r(t)=9sin⁡ti+10tj−8cos⁡tk\mathbf { r } ( t ) = 9 \sin t \mathbf { i } + 10 t \mathbf { j } - 8 \cos t \mathbf { k }r(t)=9sinti+10tj−8costk

Find the Acceleration of a Particle with the Given Position $\mathbf { r } ( t ) = 9 \sin t \mathbf { i } + 10 t \mathbf { j } - 8 \cos t \mathbf { k }$