The current I (in amperes) when 100 volts is applied to a circuit is given by $I = 5 e ^ { - 2 t } \sin t$ , where $t$ is the time (in seconds) after the voltage is applied. Approximate the current at $t = 0.8$ second after the voltage is applied. Round your answer to two decimal places.
A) $I ( 0.8 ) \approx 0.62$ ampere
B) $I ( 0.8 ) \approx 0.52$ ampere
C) $I ( 0.8 ) \approx 0.82$ ampere
D) $I ( 0.8 ) \approx 0.72$ ampere
E) $I ( 0.8 ) \approx 0.92$ ampere

Question

The current I (in amperes) when 100 volts is applied to a circuit is given by $I = 5 e ^ { - 2 t } \sin t$ , where $t$ is the time (in seconds) after the voltage is applied. Approximate the current at $t = 0.8$ second after the voltage is applied. Round your answer to two decimal places. 
A) $I ( 0.8 ) \approx 0.62$ ampere
B) $I ( 0.8 ) \approx 0.52$ ampere
C) $I ( 0.8 ) \approx 0.82$ ampere
D) $I ( 0.8 ) \approx 0.72$ ampere
E) $I ( 0.8 ) \approx 0.92$ ampere

Quizplus · Accepted Answer

The Answer of The current I (in amperes) when 100 volts is applied to a circuit is given by $I = 5 e ^ { - 2 t } \sin t$ , where $t$ is the time (in seconds) after the voltage is applied. Approximate the current at $t = 0.8$ second after the voltage is applied. Round your answer to two decimal places. 
A) $I ( 0.8 ) \approx 0.62$ ampere
B) $I ( 0.8 ) \approx 0.52$ ampere
C) $I ( 0.8 ) \approx 0.82$ ampere
D) $I ( 0.8 ) \approx 0.72$ ampere
E) $I ( 0.8 ) \approx 0.92$ ampere

The Current I (In Amperes) When 100 Volts Is Applied I=5e−2tsin⁡tI = 5 e ^ { - 2 t } \sin tI=5e−2tsint

The Current I (In Amperes) When 100 Volts Is Applied $I = 5 e ^ { - 2 t } \sin t$