Use long division to divide. $\left( 4 x ^ { 3 } - 20 x ^ { 2 } - 52 x + 8 \right) \div ( 4 x + 8 )$
A) $4 x ^ { 2 } - 7 x + 1 , x \neq - 8$
B) $4 x ^ { 2 } + 7 x + 1 , x \neq - 8$
C) $4 x ^ { 2 } - 7 x - 1 , x \neq - 8$
D) $- 4 x ^ { 2 } - 7 x + 1 , x \neq - 8$
E) $4 x ^ { 3 } - 7 x + 1 , x \neq - 8$

Question

Use long division to divide. $\left( 4 x ^ { 3 } - 20 x ^ { 2 } - 52 x + 8 \right) \div ( 4 x + 8 )$ 
A) $4 x ^ { 2 } - 7 x + 1 , x \neq - 8$
B) $4 x ^ { 2 } + 7 x + 1 , x \neq - 8$
C) $4 x ^ { 2 } - 7 x - 1 , x \neq - 8$
D) $- 4 x ^ { 2 } - 7 x + 1 , x \neq - 8$
E) $4 x ^ { 3 } - 7 x + 1 , x \neq - 8$

Quizplus · Accepted Answer

We perform long division as follows:

x^2 - 5x - 13
4x + 8 |4x^3 - 20x^2 - 52x + 8
         4x^3 + 8x^2
         -------------
                   -12x^2 - 52x
                   -12x^2 - 24x
                   ---------------
                               -28x + 8
                               -28x - 56
                               ------------
                                          64

Therefore, we have:

$$\frac{4x^3 - 20x^2 - 52x + 8}{4x + 8} = x^2 - 5x - 13 + \frac{64}{4x + 8}$$$$= x^2 - 5x - 13 + \frac{16}{x + 2}$$

So the correct answer is (A) $4 x ^ { 2 } - 7 x + 1 , x 
eq - 8$.

Use Long Division to Divide (4x3−20x2−52x+8)÷(4x+8)\left( 4 x ^ { 3 } - 20 x ^ { 2 } - 52 x + 8 \right) \div ( 4 x + 8 )(4x3−20x2−52x+8)÷(4x+8)

Use Long Division to Divide $\left( 4 x ^ { 3 } - 20 x ^ { 2 } - 52 x + 8 \right) \div ( 4 x + 8 )$