Restrict the Domain of the Function F So That the Function

Restrict the domain of the function f so that the function is one-to-one and has an in- verse function. Then find the inverse function $f ^ { - 1 }$ . State the domains and ranges of f and $f ^ { - 1 }$ $f ( x ) = ( x - 4 ) ^ { 2 }$

A) $f ^ { - 1 } ( x ) = \sqrt { x } + 4$
The domain of $f$ and the range of $f ^ { - 1 }$ are all real numbers $x$ such that $x \geq 0$
The domain of $f ^ { - 1 }$ and the range of $f$ are all real numbers $x$ such that $x \geq 4$ .
B) $f ^ { - 1 } ( x ) = \sqrt { x } - 4$
The domain of $f$ and the range of $f ^ { - 1 }$ are all real numbers $x$ such that $x \geq - 4$ .
The domain of $f ^ { - 1 }$ and the range of $f$ are all real numbers $x$ such that $x \geq 0$ .
C) $f ^ { - 1 } ( x ) = \sqrt { x } + 4$
The domain of $f$ and the range of $f ^ { - 1 }$ are all real numbers $x$ such that $x \geq 4$ .
The domain of $f ^ { - 1 }$ and the range of $f$ are all real numbers $x$ such that $x \geq 0$ .
D) $f ^ { - 1 } ( x ) = \sqrt { x } + 4$
The domain of $f$ and the range of $f ^ { - 1 }$ are all real numbers $x$ such that $x \geq 0$ .
The domain of $f ^ { - 1 }$ and the range of $f$ are all real numbers $x$ such that $x \geq - 4$ .
E) $f ^ { - 1 } ( x ) = \sqrt { x } - 4$
The domain of $f$ and the range of $f ^ { - 1 }$ are all real numbers $x$ such that $x \geq 4$ .
The domain of $f ^ { - 1 }$ and the range of $f$ are all real numbers $x$ such that $x \geq 0$ .