Find ( f / g )(x). $$f ( x ) = 5 x ^ { 2 } + x \quad g ( x ) = - 7 - x$$
A)$( f / g ) ( x ) = \frac { 5 x ^ { 2 } + x } { - 7 - x } , x \neq 0$
B)$( f / g ) ( x ) = - \frac { 5 x ^ { 2 } } { 7 } - 1 , x \neq 0$
C)$( f / g ) ( x ) = \frac { 5 x ^ { 2 } + x } { - 7 - x } , x \neq 7$
D) $( f / g ) ( x ) = \frac { 5 x ^ { 2 } + x } { - 7 - x } , x \neq - 7$
E) $( f / g ) ( x ) = \frac { 5 x + 1 } { - 7 } , x \neq 0$

Question

Quizplus · Accepted Answer

The division of $f(x)$ by $g(x)$ is directly given by $\frac{5x^2 + x}{-7 - x}$. The restriction on $x$ comes from the denominator, which cannot be zero, hence $x \neq -7$.

Find ( F / G )(X) f(x)=5x2+xg(x)=−7−xf ( x ) = 5 x ^ { 2 } + x \quad g ( x ) = - 7 - xf(x)=5x2+xg(x)=−7−x

Find ( F / G )(X) $f ( x ) = 5 x ^ { 2 } + x \quad g ( x ) = - 7 - x$