The point $P ( 16,4 )$ lies on the curve $y = \sqrt { x }$. If is the point $Q ( x , \sqrt { x } )$, use your calculator to find the slope of the secant line $P Q$ (correct to six decimal places) for the value $x = 3.89$. A) m_PQ = - 0.044439 B) m_PQ = - 0.167439 C) m_PQ = - 0.307439 D) m_PQ = 0.377439 E) m_PQ = 0.167439

Question

Quizplus · Accepted Answer

The slope of the secant line $PQ$ is calculated using the formula $\frac{\sqrt{x} - 4}{x - 16}$. Substituting $x = 3.89$, we get $\frac{\sqrt{3.89} - 4}{3.89 - 16} \approx 0.167439$.

The Point P(16,4)P ( 16,4 )P(16,4) Lies on the Curve y=xy = \sqrt { x }y=x​

The Point $P ( 16,4 )$ Lies on the Curve $y = \sqrt { x }$