Determine which one of the p-series below is divergent.
A)$\sum _ { n = 1 } ^ { \infty } \frac { 1 } { n ^ { 03 } }$
B) $\sum _ { n = 1 } ^ { \infty } n ^ { - 4 x }$
C) $\sum _ { n = 1 } ^ { \infty } \frac { 1 } { n ^ { 3 e } }$
D) $\sum _ { n = 1 } ^ { \infty } \frac { 1 } { n ^ { 4 } }$

Question

Determine which one of the p-series below is divergent. 
A)$\sum _ { n = 1 } ^ { \infty } \frac { 1 } { n ^ { 03 } }$
B) $\sum _ { n = 1 } ^ { \infty } n ^ { - 4 x }$
C) $\sum _ { n = 1 } ^ { \infty } \frac { 1 } { n ^ { 3 e } }$
D) $\sum _ { n = 1 } ^ { \infty } \frac { 1 } { n ^ { 4 } }$

Quizplus · Accepted Answer

The Answer of Determine which one of the p-series below is divergent. 
A)$\sum _ { n = 1 } ^ { \infty } \frac { 1 } { n ^ { 03 } }$
B) $\sum _ { n = 1 } ^ { \infty } n ^ { - 4 x }$
C) $\sum _ { n = 1 } ^ { \infty } \frac { 1 } { n ^ { 3 e } }$
D) $\sum _ { n = 1 } ^ { \infty } \frac { 1 } { n ^ { 4 } }$

Determine Which One of the P-Series Below Is Divergent ∑n=1∞1n03\sum _ { n = 1 } ^ { \infty } \frac { 1 } { n ^ { 03 } }∑n=1∞​n031​

Determine Which One of the P-Series Below Is Divergent $\sum _ { n = 1 } ^ { \infty } \frac { 1 } { n ^ { 03 } }$