Solve for $X$ in the equation given.
$$16 A + 12 B = - 4 X , A = \left[ \begin{array} { c c c }
5 & 6 & 3 \
- 2 & 5 & - 4
\end{array} \right] \text { and } B = \left[ \begin{array} { c c c }
- 5 & 8 & - 1 \
- 3 & - 9 & - 5
\end{array} \right]$$
A) $\left[ \begin{array} { c c c } 20 & 192 & 36 \ - 68 & - 28 & - 124 \end{array} \right]$
B) $\left[ \begin{array} { c c c } 0 & 14 & 2 \ - 5 & - 4 & - 9 \end{array} \right]$
C) $\left[ \begin{array} { c c c } - 5 & - 48 & - 9 \ 17 & 7 & 31 \end{array} \right]$
D) $\left[ \begin{array} { c c c } - 35 & 0 & - 15 \ - 1 & - 47 & 1 \end{array} \right]$
E) not possible

Question

Solve for $X$ in the equation given.
$$16 A + 12 B = - 4 X , A = \left[ \begin{array} { c c c } 
5 & 6 & 3 \
- 2 & 5 & - 4
\end{array} \right] \text { and } B = \left[ \begin{array} { c c c } 
- 5 & 8 & - 1 \
- 3 & - 9 & - 5
\end{array} \right]$$
A) $\left[ \begin{array} { c c c } 20 & 192 & 36 \ - 68 & - 28 & - 124 \end{array} \right]$
B) $\left[ \begin{array} { c c c } 0 & 14 & 2 \ - 5 & - 4 & - 9 \end{array} \right]$
C) $\left[ \begin{array} { c c c } - 5 & - 48 & - 9 \ 17 & 7 & 31 \end{array} \right]$
D) $\left[ \begin{array} { c c c } - 35 & 0 & - 15 \ - 1 & - 47 & 1 \end{array} \right]$
E) not possible

Quizplus · Accepted Answer

First, calculate $16A + 12B$. For $A$, multiply each element by 16, and for $B$, multiply each element by 12, then add the corresponding elements of the resulting matrices. The calculation yields $\left[ \begin{array} { c c c } -80 & -576 & -144 \ 272 & 112 & 496 \end{array} \right]$. Since the equation is $16A + 12B = -4X$, divide each element of the resulting matrix by $-4$ to solve for $X$, resulting in $X = \left[ \begin{array} { c c c } -5 & -48 & -9 \ 17 & 7 & 31 \end{array} \right]$.

Solve For XXX In the Equation Given A) [2019236−68−28−124]\left[ \begin{array} { c c c } 20 & 192 & 36 \\ - 68 & - 28 & - 124 \end{array} \right][20−68​192−28​36−124​]

Solve For $X$ In the Equation Given A) $\left[ \begin{array} { c c c } 20 & 192 & 36 \\ - 68 & - 28 & - 124 \end{array} \right]$