Find the mean of the distribution shown.
$\begin{array}{|l|c|c|c|}
\hline \mathrm{x} & 0 & 3 & 5 \
\hline \mathrm{P}(\mathrm{x}) & 0.36 & 0.44 & 0.20 \
\hline
\end{array}$

A) 1.00
B) 1.84
C) 2.32
D) 2.68

Question

Find the mean of the distribution shown.
$\begin{array}{|l|c|c|c|}
\hline \mathrm{x} & 0 & 3 & 5 \
\hline \mathrm{P}(\mathrm{x}) & 0.36 & 0.44 & 0.20 \
\hline
\end{array}$

A) 1.00
B) 1.84
C) 2.32
D) 2.68

Quizplus · Accepted Answer

The mean of a probability distribution is calculated as the sum of each value multiplied by its probability: $ (0 \times 0.36) + (3 \times 0.44) + (5 \times 0.20) = 0 + 1.32 + 1.00 = 2.32 $.

Find the Mean of the Distribution Shown x035P(x)0.360.440.20\begin{array}{|l|c|c|c|}\hline \mathrm{x} & 0 & 3 & 5 \\\hline \mathrm{P}(\mathrm{x}) & 0.36 & 0.44 & 0.20 \\\hline\end{array}xP(x)​00.36​30.44​50.20​​

Find the Mean of the Distribution Shown $\begin{array}{|l|c|c|c|}\hline \mathrm{x} & 0 & 3 & 5 \\\hline \mathrm{P}(\mathrm{x}) & 0.36 & 0.44 & 0.20 \\\hline\end{array}$